1.

Calculate the hydrogen ion concentration in the following biological fluids whose pH are given below: (a) Human muscle-fluid, 6.83 (b) Human stomach fluid, 1.2 (c) Human blood, 7.38 (d) Human saliva, 6.4.

Answer»

Solution :(a)Hydrogen in CONCENTRATION in Human muscle fluid (pH=6.83)
pH=-log `[H^+]`= 6.83
`therefore` log `[H^+]=-6.83 =bar7.17`
`therefore [H^+]` = Antilog `(bar7.17)`
`=1.4791xx10^(-7) APPROX 1.48xx10^(-7)`
(b)`[H^+]` in Human STOMACH [pH=12]
pH = -log `[H^+]`=1.2 and log `[H^+]` =-1.2
`therefore [H^+]` = + Antilog (1.2) = + Antilog `(bar2.8)`
`=+(6.3095xx10^(-2))`
`=6.31xx10^(-2)` M
(c) `[H^+]` in Human blood [pH=7.38]
pH=-log `[H^+]`= 7.38
`therefore` log `[H^+]=-7.38 = bar8.62`
`therefore [H^+]`= Antilog `(bar8.62)`
`=4.1687xx10^(-8) M approx 4.17xx10^(-8)` M
(d)`[H^+]` in Human SALIVA [pH=6.4]
pH=-log `[H^+]`= 6.4
`therefore` log `[H^+]=-6.4 = bar7.6`
`therefore [H^+]`=Antilog `(bar7.6)`
`=3.981xx10^(-7)` M


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