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Calculate the hydrogen ion concentration in the following biological fluids whose pH are given below: (a) Human muscle-fluid, 6.83 (b) Human stomach fluid, 1.2 (c) Human blood, 7.38 (d) Human saliva, 6.4. |
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Answer» Solution :(a)Hydrogen in CONCENTRATION in Human muscle fluid (pH=6.83) pH=-log `[H^+]`= 6.83 `therefore` log `[H^+]=-6.83 =bar7.17` `therefore [H^+]` = Antilog `(bar7.17)` `=1.4791xx10^(-7) APPROX 1.48xx10^(-7)` (b)`[H^+]` in Human STOMACH [pH=12] pH = -log `[H^+]`=1.2 and log `[H^+]` =-1.2 `therefore [H^+]` = + Antilog (1.2) = + Antilog `(bar2.8)` `=+(6.3095xx10^(-2))` `=6.31xx10^(-2)` M (c) `[H^+]` in Human blood [pH=7.38] pH=-log `[H^+]`= 7.38 `therefore` log `[H^+]=-7.38 = bar8.62` `therefore [H^+]`= Antilog `(bar8.62)` `=4.1687xx10^(-8) M approx 4.17xx10^(-8)` M (d)`[H^+]` in Human SALIVA [pH=6.4] pH=-log `[H^+]`= 6.4 `therefore` log `[H^+]=-6.4 = bar7.6` `therefore [H^+]`=Antilog `(bar7.6)` `=3.981xx10^(-7)` M |
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