Calculate the ioninc radius of a Cs^(+) ion, assuming that the cell edge length for CsCl is 0.4123 nm and the ionic radius of a Cl^(-) ion is 0.181nm.

Calculate the ioninc radius of a Cs^(+) ion, assuming that the cell ed

1.	Calculate the ioninc radius of a Cs^(+) ion, assuming that the cell edge length for CsCl is 0.4123 nm and the ionic radius of a Cl^(-) ion is 0.181nm.
Answer» 0.176nm 0.231nm 0.357nm 0.116nm Solution :(a) `r_(CS^(-))+r_(CL)=(d_(BODY))/(2)=(0.711)/(2)nm=0.3571nm` `r_(Cl^(+))=0.357-0.181=0.176nm`