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Calculate the ioninc radius of a `Cs^(+)` ion, assuming that the cell edge length for CsCl is 0.4123 nm and the ionic radius of a `Cl^(-)` ion is 0.181nm.A. 0.176nmB. 0.231nmC. 0.357nmD. 0.116nm |
Answer» (a) `r_(Cs^(-))+r_(Cl)=(d_(body))/(2)=(0.711)/(2)nm=0.3571nm` `r_(Cl^(+))=0.357-0.181=0.176nm` |
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