Saved Bookmarks
| 1. |
Calculate the ionisation energy of hydrogen atom as well as energy needed to promote its electron from first energy level to third energy level |
|
Answer» SOLUTION :Ionizationenthalpy n=5 forionization n`=prop=n_(F )` in initialelectron is inn=5so `n_(i)=5 ` hydrogen z=1 `Delta E = 2.18 xx 10^(18)((1)/(n_(1)^(2) ) - (1)/(n_(f )^(2)))= IE_(5)` `=2.18 xx 10^(18)((1)/(5^(2)) - (1)/(prop^(2)))` `=(2.18 xx 10^(18))/( 25) J` tibalanceionisationenthalpy of `IE_(5) ` and `IE_(1)` : `(1E_(5))/( 1E_(1)) = (8.72 xx 10^(20)J )/( 2.18 xx 10^(18) J) = 4.-036 xx 10^(2)= 0.04` ionizationenthalpyof n=1compareto n=5is0.04 for`n_(5)`LESSAND `n_(1)` moreionizationenthalpy `IE(5): IE (1)` `=0.04 :1` `4:100` `1: 25` So IE (1) isapprox25 timemorethan1E(5 )` |
|