1.

Calculate the ionisation energy of hydrogen atom as well as energy needed to promote its electron from first energy level to third energy level

Answer»

SOLUTION :Ionizationenthalpy n=5
forionization n`=prop=n_(F )`
in initialelectron is inn=5so `n_(i)=5 ` hydrogen
z=1
`Delta E = 2.18 xx 10^(18)((1)/(n_(1)^(2) ) - (1)/(n_(f )^(2)))= IE_(5)`
`=2.18 xx 10^(18)((1)/(5^(2)) - (1)/(prop^(2)))`
`=(2.18 xx 10^(18))/( 25) J`
tibalanceionisationenthalpy of `IE_(5) ` and `IE_(1)` :
`(1E_(5))/( 1E_(1)) = (8.72 xx 10^(20)J )/( 2.18 xx 10^(18) J) = 4.-036 xx 10^(2)= 0.04`
ionizationenthalpyof n=1compareto n=5is0.04
for`n_(5)`LESSAND `n_(1)` moreionizationenthalpy
`IE(5): IE (1)`
`=0.04 :1`
`4:100`
`1: 25`
So IE (1) isapprox25 timemorethan1E(5 )`


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