Calculate the ionization energy for a lithium atom. – InterviewSolution

InterviewSolution

1.	Calculate the ionization energy for a lithium atom.
Answer» For `3^(Li^(7))` atom, `Z=3, n=2 [because Li =1s^(2) 2s^(1)]` `E_(n)=(13.6Z^(2))/(n^(2))eV` `=(13.6xx(3)^(2))/(4)=30.6 eV` `therefore` Ionization energy of Lithium =30.6 eV.

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