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Calculate the K_b of hydrazine, if pH of 4 xx 10^(-3) M hydrazine is 9.7. |
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Answer» Solution :`POH -PH =14-9.7 =4.3` `pOH =(pk_b- log C)/(2) ` ` 4.3=(pK_b - log (4 XX 10^(-3)))/(2 ) implies pk_a = 6.2` ` k_b =10^(-6.2) = 6.30xx 10^(-7)` |
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