Calculate the K. E of 6 moles of nitrogen at 25 °c

1.	Calculate the K. E of 6 moles of nitrogen at 25 °c
Answer» $\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}}$ Given : Moles of NITROGEN = 6 Temperature = 25+273 = 298 K To Find : Kinetic ENERGY of nitrogen gas Formula : Average kinetic energy of gas molecules is GIVEN as... $\: \: \: \: \: \boxed{ \green{ \bold{ \huge{ \rm{KE = \frac{3}{2} nK{ \tiny{b}}T}}}}}$ Where KB = boltzman constant Calculation : $\rm \: KE = \frac{3}{2} \times 6 \times 1.38 \times {10}^{ - 23} \times 298 \\ \\ \star \: \boxed{ \rm{ \pink{KE = 3.7 \times {10}^{ - 20} \: J}}}$

Answer»

$\blue{\underline{ \huge{ \blue{\boxed{ \mathfrak{\fcolorbox{red}{orange}{\purple{Answer}}}}}}}}$

Moles of NITROGEN = 6

Temperature = 25+273 = 298 K

Kinetic ENERGY of nitrogen gas

Average kinetic energy of gas molecules is GIVEN as...

$\: \: \: \: \: \boxed{ \green{ \bold{ \huge{ \rm{KE = \frac{3}{2} nK{ \tiny{b}}T}}}}}$

Where KB = boltzman constant

$\rm \: KE = \frac{3}{2} \times 6 \times 1.38 \times {10}^{ - 23} \times 298 \\ \\ \star \: \boxed{ \rm{ \pink{KE = 3.7 \times {10}^{ - 20} \: J}}}$

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