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Calculate the lattice energy of `NaCI` crystal from the following data by the use of Born-Haber cycle. Sublimation energy of `Na = 26 kcal//g`atom, dissociation energy of `CI_(2) = 54 kcal//"mole"`, ionisation energy of `Na(g) = 117 kcal//"mol"`, electron affinity for `CI(g) = 84 kcal//g` atom, heat of formation of `NaCI =- 99 kcal//"mole"`. |
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Answer» Correct Answer - `[-185 kcal//"mole"]` `[(DeltaH)_("formation") = (DeltaH)_("sub") +I.E. +(DeltaH)_(eg) +1//2 (DeltaH)_("diss") +U]` |
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