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Calculate the length of a seconds pendulum at a place where g = 9.81 m/s2 . |
Answer» Data : T = 2 s, g = 9.81 m/s2 Period of a simple pendulum, T = 2π \(\sqrt{\frac{L}{g}}\) For a seconds pendulum, 2 = 2π \(\sqrt{\frac{L}{g}}\) ∴ The length of the seconds pendulum, L = \(\frac{g}{\pi^2}\) = \(\frac{9.81}{(3.142)^2}\) = 0.9937 |
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