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Calculate the magnetic field due to a circular coil of `250` turns and of diameter `0*1m`, carrying a current of `7A` (i) at the center of the coil (ii) at a point on the axis of the coil at a distance `0*12m` from the center of the coil. |
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Answer» Correct Answer - (i) `2*2xx10^-2T` (ii) `1*25xx10^-3T` (i) `B=(mu_0)/(4pi)(2pinI)/(r)` `=(10^-7xx2xx(22//7)xx250xx7)/((0*1//2))=2*2xx10^-2T` (ii) `B=(mu_0)/(4pi)(2pinIa^2)/((a^2+x^2)^(3//2))` `=(10^-7xx2xx(22//7)xx250xx7xx(0*1//2)^2)/([(0*1//2)^2+(0*12)^2]^(3//2))` `=1*25xx10^-3T` |
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