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Calculate the magnetic field intensity at a distance of `20cm.` from a pole of strength `40Am` in air. Find the magnetic induction at the same point. |
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Answer» Correct Answer - `79*54Am^-1`; `10^-4Wb//m^2` Here, `d=20cm=1//5m, m=40Am`, `H=?, B=?` `H=(1)/(4pi)(mxx1)/(d^2)=(1xx7)/(4xx22)xx (40)/((1//5)^2)=79*54Am^-1` `B=mu_0H=4pixx10^-7xx79*54=10^-4Wbm^-2` |
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