Calculate the magnitude of linear acceleration of a particle moving in a circle of radius ` 0.5 m` at the instant when its angular velocity is ` 2/5 rads^(-1)` and its angular acceleration is `6 rad s^(-2)`.

Calculate the magnitude of linear acceleration of a particle moving in

1.	Calculate the magnitude of linear acceleration of a particle moving in a circle of radius ` 0.5 m` at the instant when its angular velocity is ` 2/5 rads^(-1)` and its angular acceleration is `6 rad s^(-2)`.
Answer» Here, `r-0.5 m, xx 6=3.0 ms^(-1)` `alpha =6 rad s^(-2)` Tangential acceleration, `a_(T) =ralpha =0.5 xx 6= 3. 0 ms^(-2)` Centripetal acceleration, Magintude of total linear accr.rtation, `a = sqrt (a_(T)^(2) + a_(C)^(2) = sqrt ((3.0) ^(2) + (3.125 )^(2))` `=4. 33 ms^(-2)`.

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Calculate the magnitude of linear acceleration of a particle moving in a circle of radius ` 0.5 m` at the instant when its angular velocity is ` 2/5 rads^(-1)` and its angular acceleration is `6 rad s^(-2)`.

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