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Calculate the mass of Ag deposited at cathode when a current of 2 ampere was passed through a solution for 15 minutes. |
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Answer» Correct Answer - 2.014 g Reaction at cathode is : `underset(1F(1xx96500" C"))(Ag^(+)(aq))+e^(-) to underset(1" mol"(108 g))(Ag(s))` 96500C of charge is required to deposit Ag=108 g. 1800 C of charge required to deposit `Ag=(108 g)xx((1800 C))/((96500C))=2.014 g`. |
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