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Calculate the mass of Ammonia present in 1.5 x 10^ 23 molecules |
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Answer» MASS of 1 mole of NH3 MOLECULE = 17 G. So 6.023 X 1023 MOLECULES = 17g ∴1.5 x 1023 molecules = 17/ 6.023 x 1023 * 1.5 x 1023 molecules = 4.23 g |
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