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Calculate the mass of H_2SO_4 present in 250 cm of a seminormal solution. |
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Answer» Solution :According to the normality relation, `W=(Nev)/1000` In the PRESENT case, `N=1/2` (solution is seminormal) `E = ("Molecular mass")/("BASICITY")` `=98/2 = 49` `V = 250 cm^(3)` `therefore w =(1/2 xx 49 xx 250)/1000 = 6.125 G` Hence, the given solution contains 6.125 g of `H_(2)SO_(4)` |
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