Calculate the mass of (i) 1022 atoms of sulphur.(ii) 0.1 mole of ca

1.	Calculate the mass of (i) 1022 atoms of sulphur.(ii) 0.1 mole of carbon dioxide. [Atomic mass : S = 32, C = 12 and 0 = 16 and Avogadro's Number = 6 x 1023]
Answer» Molecular formula = (CH₂Br) x 2 = C₂H₄Br₂ (i) 1 mole of sulphur = 6 x 10²³ atoms = 32 g of sulphur 10²² atoms = (32 x 10²²)/(6 x 10²³) = 32/60 = 0.533 g (ii) 1 mole of carbon dioxide (CO₂) = 12 + (2 x 16) = 44 g 0.1 mole of carbon dioxide = 0.1 x 44 = 4.4 g

Calculate the mass of (i) 1022 atoms of sulphur.(ii) 0.1 mole of carbon dioxide. [Atomic mass : S = 32, C = 12 and 0 = 16 and Avogadro's Number = 6 x 1023]

Answer»

Molecular formula = (CH₂Br) x 2 = C₂H₄Br₂

(i) 1 mole of sulphur = 6 x 10²³ atoms = 32 g of sulphur

10²² atoms = (32 x 10²²)/(6 x 10²³) = 32/60 = 0.533 g

(ii) 1 mole of carbon dioxide (CO₂) = 12 + (2 x 16) = 44 g

0.1 mole of carbon dioxide = 0.1 x 44 = 4.4 g