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Calculate the mass of lime that can be prepared by heating 200 kg of limestone that is 90% pure CaCO_3 CaCO_3 to CaO + CO_2 100 kg xx 10^(-3)"" 56 kg xx 10^(-3) |
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Answer» Solution :`200kg ` of `90%` PURE `CaCO_3 = 200 xx (90)/(100)` `=180 KG ` pure ` CaCO_3` ` 100 xx 10^(-3)` kg of pure `CaCO_3 ` on heating gives ` 56 xx 10^(-3)` kg of CaO 180 kg of `CaCO_3` gives on heating `=(56 xx 10^(-3) xx 180)/( 100 xx 10^(-3))` `= 100.8 kg ` CaO |
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