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Calculate the mass of oxygen obtained by complete decomposition of 10kg of pure potassium chlorate (Atomic mass K=39, O=16 and Cl = 35.5) 2KClO_3 to 2KCl+ 3O_2 |
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Answer» SOLUTION :MOLECULAR mass of `KClO_3 = 39 + 35.5 + 48 = 122. 5` Molecular mass of `O_2 = 16 + 16 = 32` According to the Stoichiometric equation written above ` ( 2 xx 122.5) xx 10^(-3)`KG of `KClO_3` on heating gives `(3 xx 32) xx 10^(-3)` kg of oxygen . 10 kg of `KClO_3` gives =`(3 xx 32 xx 10^(-3))/( 2 xx 122.5 xx 10^(-3)) xx 10` `=3 .92 kg ` of O_2` |
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