Calculate the mass of oxygen required at STP to convert 2.4g of graphite into carbon dioxide?What is orbital? How is it different from Bohr's orbit?

Calculate the mass of oxygen required at STP to convert 2.4g of graphi

1.	Calculate the mass of oxygen required at STP to convert 2.4g of graphite into carbon dioxide?What is orbital? How is it different from Bohr's orbit?
Answer» CHEMICAL equation for the PROCESS is:C+O2 →CO 2 For the above reaction, 1 mole of O 2 will burn 1 mole of C completely.In 2.4 g C, number of moles =122.4 =0.2 moles of oxygen is required.Volume OCCUPIED by 1 mole of an ideal gas at STP (T=0K and P=1atm) is 22.4L. Therefore, 0.2 mol O 2 =0.2×22.4 L =4.48L.