Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make

1.	Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.
Answer» 0.375 M aqueous solution od sodium acetate `-=` 1000 mL of solution containing 0.375 moles of sodium acetate `therefore ` Number of moles of sodium aceate in 500 ml `=(0.375 )/(1000)xx500` `=0.1875 ` mole Molar mass of sodium acetate = 82.0245 g `"mole"^(-1)` (Given ) `therefore ` Required mass of sodium acetate `=(82.0245 g mol ^(-1) ) (0.1875 "mole")` =15.38 g

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Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

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