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Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^(–1). |
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Answer» Solution :Molarity of an aqueous solution is given by `W=(MM.V)/1000` In the present case, `M=0.375, M. 82.0245, V=500 mL, w`=? SUBSTITUTING the VALUES, we get `w=(0.375 XX 82.0245 xx 500)/1000 = 15.38 g` Here, mass of sodium ACETATE required = 15.38 g. |
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