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Calculate the mass of the following atoms in amu(a) Helium (mass of He = 6.641xx10^(-24)g)(b) Silver (mass of Ag = 1.790xx10^(-22) g) |
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Answer» Solution :1 amu = `1.66056xx10^(-24)` (a) The MASS of Helium atom in amu =`(6.641xx10^(-24))/(1.66056xx10^(-24))`= 3.9992 amu. (b)The mass of SILVER atom in amu = `(1.790xx10^(-22))/(1.66056xx10^(-24))` = 107.79 amu |
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