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Calculate the mass of the following atoms in amu, (a) Helium (mass of He = 6.641 x 10-24 g) (b) Silver (mass of Ag = 1.790 x 10-22 g) 1 amu = 1.66056 x 10-24 |
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Answer» (a) The mass of Helium atom in amu = \(\frac{6.641\times10^{-24}}{1.66056\times10^{-24}}\) = 3.9992 amu. (b) The mass of Silver atom in amu = \(\frac{1.790\times10^{-22}}{1.66056\times10^{-24}}\) = 107.79 amu. |
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