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Calculate the mass of urea `(NH_(2)CONH_(2))` required in making `2.5 kg `of `0.25 `molal aqueous solution.A. 37 gB. 35 gC. 34 gD. 32 g |
Answer» Correct Answer - a Mass of solvent = 1000 g Molar mass of urea `(NH_(2)CONH_(2)) = 60 g mol^(-1)` `0.25` mole of urea `= 0.25xx60 = 15g` Total mass of solution `= 100 + 15 = 1.015 kg` 1.015 kg of solution contain urea `= 15 g` 2.5 kg of solution `= (15)/(1.015)xx2.5 = 37 g` |
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