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Calculate the mass per cent of different elements present in sodium sulphate (Na_2SO_4) |
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Answer» Solution :Gram molecular mass of `Na_2SO_4` `=(2 xx 22.99) + 32.06 + (4 xx 16.00) = 142.04 G MOL^(-1)` Mass per CENT of an element `=("Mass of the element in one MOLE of the compound")/("Gram molecular mass of the compound") xx 100` `therefore` Mass % of sodium `=(22.99 xx 2)/(142.04)xx 100 = 32.37 %` Mass % of sulphur `=32.06/(142.04) xx 100 = 22.57 %` Mass % of OXYGEN `=(16.00 xx 4)/(142.04) xx 100 = 45.06 %` |
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