1.

Calculate the mass percentage of B4 in Na2B4O7.10H2O​

Answer»

Answer:

Na= 23*2

B=10.8*4

O=16*7

H= 1

Na2B4O7.10H2O = 46+43.2+112+10*(2+16)

=381.2

B4= 43.2/381.2*100

=11.33



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