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Calculate the maximum energy that a `beta` particle can have in the following decay: `._(8)O^(19) to ._(9)F^(19)+._(-1)e^(0)+barnu` Given, `m(._(8)O^(19))=19.003576u, m(._(9)F^(19))=18.998403u, m(._(-1)e^(0))=0.000549u` |
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Answer» Correct Answer - 4.3049 MeV Q-value of `beta`-decay =`(m(._8O^19) -{m(._9F^19) + m(._(-1)e^0)}` The energy is shared by `beta^-` particle , if `barv` does not get any share. |
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