Saved Bookmarks
| 1. |
Calculate the maximum frequency deviation for the FM signal v(t) = 10 cos (6000t+ 5sin2200t) a. 2200 Hz b. 6000 Hz c. 1750 Hz d. 11000 Hz |
|
Answer» c. 1750 Hz A standard FM signal is represented by v(t) = Ac cos(2πfct + kfsin2πfmt) Ac = carrier amplitude fc = carrier frequency kf = modulation index fm = modulating frequency = 2200/2π = 350 Hz kf = frequency deviation/modulating frequency 5 = freq deviation/ 350 Therefore, deviation = 5 * 350 = 1750Hz |
|