1.

Calculate the maximum frequency deviation for the FM signal v(t) = 10 cos (6000t+ 5sin2200t) a. 2200 Hz b. 6000 Hz c. 1750 Hz d. 11000 Hz

Answer»

c. 1750 Hz 

A standard FM signal is represented by

v(t) = Ac cos(2πfct + kfsin2πfmt)

Ac = carrier amplitude

fc = carrier frequency

kf = modulation index

fm = modulating frequency = 2200/2π = 350 Hz

kf = frequency deviation/modulating frequency

5 = freq deviation/ 350

Therefore, deviation = 5 * 350

= 1750Hz



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