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Calculate the maximum horizontal range attained by the particle in the case of oblique projection. |
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Answer» Solution :We know that HORIZONTAL range , `R = (U^(2) sin 2 THETA)/( g)` for R tobe maximum u and g are constant. Therefore variable is ` ' theta'`. i.e., `sin 2 theta = 90^(@)` ` :. theta = 45^(@)` |
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