1.

Calculate the maximum horizontal range attained by the particle in the case of oblique projection.

Answer»

Solution :We know that HORIZONTAL range ,
`R = (U^(2) sin 2 THETA)/( g)`
for R tobe maximum u and g are constant.
Therefore variable is ` ' theta'`.
i.e., `sin 2 theta = 90^(@)`
` :. theta = 45^(@)`


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