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Calculate the maximum kinetic energy of the β particle emitted in the following decay equation in MeV.7N12→ 6C12∗+ +1e0+ν6C12∗→ 6C12+ γ (4.43 MeV)The atomic mass of N12 is 12.018613 u. The atomic mass of C12 is 12 u. |
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Answer» Calculate the maximum kinetic energy of the β particle emitted in the following decay equation in MeV. |
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