Calculate the maximum power transferred.(a) 1.79W(b) 4.55W(c) 5.67W(d) 3.78WThe question was asked in unit test.This interesting question is from Maximum Power Transfer topic in division Network Theorems of Basic Electrical Engineering

Calculate the maximum power transferred.(a) 1.79W(b) 4.55W(c) 5.67W(d)

1.	Calculate the maximum power transferred.(a) 1.79W(b) 4.55W(c) 5.67W(d) 3.78WThe question was asked in unit test.This interesting question is from Maximum Power Transfer topic in division Network Theorems of Basic Electrical Engineering
Answer» CORRECT choice is (a) 1.79W Easiest explanation: On shorting the VOLTAGE sources: RL=3\|\|2+4\|\|3 =1.20+1.71=2.91 ohm. The two NODAL EQUATIONS are: (VA-10)/3+VA/2=0 (VB-20)/4+VB/3=0 On solving the two equations, we get VA=4V, VB=8.571V. VAB=VA-VB = 4V – 8.571V = -4.57V. Eth=4.57V The maximum power transferred = Eth^2/4RL. SUBSTITUTING the given values in the formula, we get Pmax = 1.79W.

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