Calculate. The molairy of solution containing in 45gof glucose in 250c

1.	Calculate. The molairy of solution containing in 45gof glucose in 250cmcube of solution
Answer» ANSWER: 1M FORMULA used: $MOLARITY=\frac{MASS(<klux>SOLUTE</klux>)}{MOLAR MASS} \frac{1000}{VOLUME}(ml)$ Explanation:* Given, Mass(solute)=45 g Volume= 250 cm³ Molar mass of Glucose (C₆H₁₂O₆) 6×12+12×1+6×16 = 180 u. Using formula of Molarity we GET, $\frac{45}{180}* \frac{1000}{250}$ $=0.25*4\\=1M$

Calculate. The molairy of solution containing in 45gof glucose in 250cmcube of solution

Answer»

Given,

Mass(solute)=45 g

Volume= 250 cm³

Molar mass of Glucose (C₆H₁₂O₆)

6×12+12×1+6×16

= 180 u.

Using formula of Molarity we GET,

$\frac{45}{180}* \frac{1000}{250}$

$=0.25*4\\=1M$