

InterviewSolution
Saved Bookmarks
1. |
Calculate the molal depression constant of a solvent which has freezing point `16.6^(@)C` and latent heat of fusion `180.75 Jg^(-1)`A. `2.68`B. `3.86`C. `4.68`D. `2.86` |
Answer» Correct Answer - B `K_(f)=(RT_(f)^(2))/(1000xx L_(f)), R=8.314 JK^(-1)mol^(-1)` `T_(f)=273+16.6=289.6K , L_(f)=180.75 Jg^(-1)` `K_(f)=(8.314xx289.6xx289.6)/(1000xx180.75)=3.86` |
|