Calculate the molality of an aqueous solution containing 3.0g of urea (mol.mass=60) in 250g of water.

Calculate the molality of an aqueous solution containing 3.0g of urea

1.	Calculate the molality of an aqueous solution containing 3.0g of urea (mol.mass=60) in 250g of water.
Answer» SOLUTION :Mass of solute= 3.0 g Moles of solute `=( " Mass of solute ")/(" Molar mass ")` ` = (3.0g )/( 60 g " mol "^(-1))`= 0.05 mol Mass of Solvent = 250 g `= (250)/(1000) = 0.25 kg ` Molality of solution `= (" Moles of solute ")/(" Mass of Solvent in kg . ")` `= (0.05 Mol )/( 0.25 kg ) =0.2 `m