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Calculate the molar concentration of O2 in water at 25°c under atmospheric condition where the partial pressure of O2 is 0.22 atm .the Henry's law constant for O2 is 1.3×10^-3 mol/L.atm |
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Answer» <P>Explanation: According to HENRY's law, P=K H
×x ∴x O 2
= K H
P O 2
= 4.34×10 4
0.2
=4.6×10 −6
Moles of water= 18 1000
=55.5mol ∴x O 2
= H 2
O
+n O 2
n O 2
≈ n H 2
O
n O 2
⇒n O 2
=4.6×10 −6 ×55.5=2.55×10 −4 mole ∴ Molarity = 2.55×10 −4 M |
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