Calculate the molar conductivity of acetic acid at infinite dilution. Given that molar conductivity of `HCl. CH_(3)COONa` and NaCl is 426.1,91.0 and 126.5 `ohm^(-1)cm^(2)"mol"^(-1)` respectively.A. `390-6ohm^(-1)cm^(2)"mol"^(-1)`B. `195.3ohm^(-1)cm^(2)"mol"^(-1)`C. `585.9ohm^(-1)cm^(2)"mol"^(-1)`D. `292.95ohm^(-1)cm^(2)"mol"^(-1)`

Calculate the molar conductivity of acetic acid at infinite dilution.

1.	Calculate the molar conductivity of acetic acid at infinite dilution. Given that molar conductivity of `HCl. CH_(3)COONa` and NaCl is 426.1,91.0 and 126.5 `ohm^(-1)cm^(2)"mol"^(-1)` respectively.A. `390-6ohm^(-1)cm^(2)"mol"^(-1)`B. `195.3ohm^(-1)cm^(2)"mol"^(-1)`C. `585.9ohm^(-1)cm^(2)"mol"^(-1)`D. `292.95ohm^(-1)cm^(2)"mol"^(-1)`
Answer» Correct Answer - A The degree of dissociation `(a)=(^^_(m)(CH_(3)COOH))/(^^_(m)(CH_(3)COOH))=(11.7)/(40.9+394.1)=0.03`,

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