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Calculate the molarity of a solution obtained by mixing 250 mL of `0.5` M HCl with 750 mL of 2 M HCl.A. `1.8`B. `2.0`C. `1.6`D. `0.8`

Answer» `N_("Mixture")=(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))`
` = ((0.5)250+(2xx750))/(250+750) = 1.625`N
`:. ` Molarity = 1.625 N(as HCl is monobasic acid)


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