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Calculate the molarity of a solution of ethanol in water in which the mole fraction of ethanol is 0.040. ( assume the density of water to be one). |
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Answer» MOLE of `H_(2)O` in 1 litre `=(1000g)/(18) = 55.55` mole For BINARY solution, `X_(1)+X_(2)=1` `X_(H_(2)O) = 1 - X_(C_(2)H_(5)OH)` `X_(H_(2)O)=1-0.040=0.96` `X_(H_(2)O)=(n_(H_(2)O))/(n_(H_(2)O)+n_(C_(2)H_(5)OH))` `0.96=(55.55)/(55.55+n_(C_(2)H_(5)OH))` `53.328 + 0.96 n_(C_(2)H_(5)OH)=55.55` `n_(C_(2)H_(5)OH)=(2.222)/(0.96) = 2.3145` mole In 1 L solution 2.3145 mole `=2.3145` |
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