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Calculate the molarity of a solution of ethanol in water, in which the mole fraction of ethanol is 0.040 (assume the density of water to be one). |
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Answer» SOLUTION :Number of moles in 1 L of WATER = `1000/18 = 55.55` Assuming the given solution to be dilute, we have in 1 L of solution, Mole fraction of ETHANOL `=("No. of moles of ethanol")/("No. of moles of ethanol + No. of moles of water.)` or `0.040 = ("No. of moles of ethanol")/("No. of moles of ethanol" + 55.55")` `=(55.55 xx 0.040)/(1-0.040)= 2.314` Thus, 2.314 moles of ethanol are present in 1 L solution. Hence, MOLARITY of the given solution = 2.314 M. |
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