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Calculate the molarity of `H^(+)` ions obtained by mixing 200 ml of 0.5 M `H_(2)SO_(4)` solution `(d_("solution"=xgm//ml)`, 100 ml of 0.7 M `HNO_(3))` solution `(d_("solution")=1.2xxgm//ml)` and 100 ml of 0.3 M HCl solution `(d_("solution")=1.3xxgm//ml)` such that density of final solution is 1.5xx gm//ml`. |
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Answer» mmole of `H^(+)` ions `=200xx0.5xx2+10xx0.7+100xx0.3=300` `V_("final")` of solution `=(200x+120x+130x)//` `d_("final solution")=(450x)/(1.5x)` `V_("final")=300ml` `[H^(+)]=(300)/(100)=1` |
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