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Calculate the molarity of pure water at room temperature if its density is 0.998 g cm^(-3) |
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Answer» Solution :MASS of `1000 cm^(3)`of pure WATER = Density `xx` Volume `=0.998 xx 1000 = 998 g` MOLECULAR Mass of water `=2+16 = 18` `therefore` NUMBER of moles of water present in `1000 cm^(3)` `=998/18 = 55.44` Hence, the molarity of pure water at room temperature is 55.44 M. |
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