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1. |
Calculate the molarity of water if its density is `1000 kg//m^(3)`. |
Answer» Density of water `= ((1000kg))/(m^(3))=((100xx10^(3)g))/(("100 cm")^(3))=1 g cm^(-3)=1 g mL^(-1)` Mass of 1L(1000mL) of water `=(1000 mL)xx(1g mL^(-1))=100g` Molarity of water `= ("Mass of water/Molar mass")/("Volume of water")` `=((1000g))/((18"g mol"^(-1))xx"1 L")=55.56 "mol L"^(-1)=55.56M`. |
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