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Calculate the mole fraction of benzene is solution containing 30% by mass in carbon tetrachloride. |
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Answer» Solution :`30%` of beneze in carbon tetrachloride by mass means that Mass of benzene in the solution = 30 g Mass of solution = 100 g `therefore` Mass of carbon tetrachloride `= 100g - 30G = 70g` Molar mass of benzene `(C_(6) H _(6)) = 78 mol^(-1)` Molar mass of `C Cl_(4) = 12 +(4 xx 35.5) = 154 g mol^(-1)` `therefore` No. of moles of benzene `= ("Mass")/("Molar mass") = (30g)/(78 mol ^(-1)) = 0.385` No. of moles of `C Cl _(4) = ("Mass")/("Molar mass") = (70g)/(154 g mol ^(-1)) =0.455` Mole fraction of benzene `= ("Moles of benzene")/("Total moles in the solution")` `= (0.385)/(0.385 + 0.455) = (0.385)/(0.84) = 0.458` Mole fraction of `C Cl_(4) =1- 0.458 =0.542` |
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