Calculate the mole fraction of Ethanol (C_(2)H_(5)OH) in the solution containing 20 g of Ethanol and 100 g of water.

Calculate the mole fraction of Ethanol (C_(2)H_(5)OH) in the solution

1.	Calculate the mole fraction of Ethanol (C_(2)H_(5)OH) in the solution containing 20 g of Ethanol and 100 g of water.
Answer» Solution :Weight of ETHANOL `=20g` Weight of water `=100G` Molecular MASS of `C_(2)H_(5)-OH=-46` No of moles of ethanol `=20/46=0.4348` moles `n_(8)=` NO. of moles of water `=100/18=5.555` moles `X_(A)=` Mole fraction of ethanol `=(n_(A))/(n_(A)+n_(a))=0.4348/(0.4348+5.555)=0.4348/5.9898` `X_(A)=0.07259`