Calculate the mole fraction of ethelene glycol (C2H6O2) in a solution

1.	Calculate the mole fraction of ethelene glycol (C2H6O2) in a solution containing 20% by mass.
Answer» Answer: Here is the answer ....please do MARK meh the brainliest Explanation: 20% of C2H6O2 by mass is present. That means solution has 20 G of ethylene glycol and 80 g of WATER. Now, Molar mass of C2H6O2 = 12 x 2 + 1 x 6 + 2 x 16 = 62 g mol-1 . Moles of C2H6O2 = 20 / 62 = 0.322 moles Moles of water = 80 / 18 = 4.444 moles Mole fraction of ethylene glycol = 0.322 / 0.322 + 4.444 = 0.068 Mole fraction of water = 1 - 0.068 = 0.932

Calculate the mole fraction of ethelene glycol (C2H6O2) in a solution containing 20% by mass.

Answer»

Answer:

Here is the answer ....please do MARK meh the brainliest

Explanation:

20% of C2H6O2 by mass is present.

That means solution has 20 G of ethylene glycol and 80 g of WATER.

Now,

Molar mass of C2H6O2 = 12 x 2 + 1 x 6 + 2 x 16 = 62 g mol-1 .

Moles of C2H6O2 = 20 / 62 = 0.322 moles

Moles of water = 80 / 18 = 4.444 moles

Mole fraction of ethylene glycol = 0.322 / 0.322 + 4.444 = 0.068

Mole fraction of water = 1 - 0.068 = 0.932