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Calculate the molecular diameter of helium from its van der Waals constant `b`. `(b=24cm^(3)mol^(-1))` |
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Answer» Since `b=4xx` Volume occupied by the molecules in `1 mol` of a gas or `b=4 N_(A)((4)/(3)pi r^(3))` `:. R=((3b)/(16 N_(A)pi))^(1//3)` `={(3xx24)/(16(6.023xx10^(23))(3.14))}^(1//3)` `=1.335xx10^(-8)cm=133.5 Pm` `:. D=2r=2xx133.5 Pm=267 Pm` |
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