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Calculate the moles of `CO_(2)` obtained when `0.274` mole Of `C_(2) H_(5)OH` is burnt in air.A. `0.548`B. `0.0548`C. `0.558`D. `0.058` |
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Answer» Correct Answer - A `underset(underset(0.274 "mol")(1"Mol"))(C_(2)H_(5)OH)+3O_(2)rarr underset(2"mol")(3 "CO")_(2)+3H_(2)O` 1 mole of `C_(2)H_(5)OH` prodluces 2 moles of `CO_(2)` `therefore 0.274` mole of `C_(2)H_(5)OH` will produce `(CO_(2)` `=2/1xx 0.274` `=2xx 0.274=0.548` mol Thus, `0.548` mole of `CO-(2)` is obtained from `0.273` mole ` C_(2) H_(5)OH.` |
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