1.

Calculate the moment of inertia of a cylinder of length 2 m, radius 5 cm and density 8 xx 10^(3) kg//m^3 about (i) the axis of the cylinder and (ii) and axis passing through the centre and perpendicular to its length.

Answer»


Solution :`M=piR^(2)ID = 125.6 kg` (i) `I = MR^(2)//2 = 0.157 kg m^(2)`, (II) `I =(MR^(2)//4) + (Ml^(2)//12) + (Ml^(2)//12) = 41.94 kgm^(2)`


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