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Calculate the momentum of a moving particle which has a de broglie wavelength of 200pm |
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Answer» 3.313 ×10^-34 kgms^-1 {tex}Momentum=3.313×10^-24kgms-{/tex}Explanation:Here,de-broglie wavelength.wavelenght=h/mv200× 10-12=6.626×10-34/p[1pm=10-12m,h=6.626×10-34]p=6.626×10-34/200×10-12p=6.626×10-34/2×10-10p=3.313×10 -34+10p=3.313×10-24kgms- |
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