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Calculate the momentum of a particle which has a de Brglie wavelength of `1 Å` or 0.1 nm. `(h = 6.6 xx 10^(-34) kg m^(2) s^(-1))`

Answer» Correct Answer - `6.6 xx 10^(-24) kg ms^(-1)`
`lamda = (h)/(p) or p = (h)/(lamda) = (6.6 xx 10^(-34) kg m^(2) s^(-1))/(10^(-10)m) = 6.6 xx 10^(-24) kg m s^(-1) (1 Å = 10^(-10)m, 1nm = 10^(-9) m)`


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